If the cell potential value is negative for a cell constructed by attaching a standard hydrogen electrode to another half-cell,then the other half-cell will be:
$(i)$ Anode or cathode?
$(ii)$ Positive or negative?
$(iii)$ On left side or right side?
$(i)$ Anode or cathode?
$(ii)$ Positive or negative?
$(iii)$ On left side or right side?
(A) The cell potential $E_{cell}$ is given by $E_{cell} = E_{cathode} - E_{anode}$.
Given that the standard hydrogen electrode $(SHE)$ has a potential of $0.00 \ V$,if the cell potential is negative,it implies that the potential of the other half-cell is lower than the $SHE$.
$(i)$ Since the other half-cell has a lower potential,it acts as the $Anode$ (oxidation occurs here).
$(ii)$ The $Anode$ in a galvanic cell is the $Negative$ electrode.
$(iii)$ By convention,the $Anode$ is placed on the $Left$ side of the cell diagram.
Given that the standard hydrogen electrode $(SHE)$ has a potential of $0.00 \ V$,if the cell potential is negative,it implies that the potential of the other half-cell is lower than the $SHE$.
$(i)$ Since the other half-cell has a lower potential,it acts as the $Anode$ (oxidation occurs here).
$(ii)$ The $Anode$ in a galvanic cell is the $Negative$ electrode.
$(iii)$ By convention,the $Anode$ is placed on the $Left$ side of the cell diagram.
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